Cleveland Indians Currently Most Dangerous Team in AL

Jesse Johnson-USA TODAY Sports

The team no one wants to play in the MLB AL playoffs right now are the Cleveland Indians. The Detroit Tigers might beg to differ with that statement since they dominated the Indians all season.

But right now, the Indians are a hungry team and a very dangerous one. They will probably have to win all three of their remaining regular-season games to secure the second Wild Card spot, but they’re too hot even for a team like the Tampa Bay Rays to cool off should the two teams meet in the one-game Wild Card battle next week.

Once the Indians make it to the best-of-five series in the AL playoffs, it’s not going to be easy for their opponents.

They are on a seven-game winning streak and have won 12-of-their last 14 games. They are 18-6 this month and are likely to keep working on the Minnesota Twins this weekend and stretch that record to 21-6.

Manager Terry Francona knows something about coaching a team to championship contention, and has the Cleveland players confident they can win regardless of the circumstances.

Currently, Cleveland has a 21-win improvement from a year ago, which is the second largest year-to-year jump in wins in franchise history. The Indians are having some concerns with their bullpen right now, but they’re finding ways to overcome any type of struggles they might be having.

Jason Giambi‘s a dramatic two-out walk-off home run against the Chicago White Sox earlier this week sent a message loud and clear to the rest of the AL that no one is about to end the Indians’ date with destiny.

John Raffel is a writer for RantSports.comFollow him on Twitter  @JohnCarlRaffel, Like” him on Facebook or add him to your network on Google.

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