Green Bay Packers quarterback Aaron Rodgers was named the National Football Conference Player of the Week for his outstanding performance against the New Orleans Saints this past Sunday. The Packers were able to defeat the Saints 28-27 due to Rodgers’ superb play.
Rodgers completed 75.6 percent of his passes (31-for-41) for 319 yards and four touchdowns for a 119.9 passer rating. Rodgers went head-to-head with Drew Brees and for the second consecutive season both signal callers put on quite the show. Even though Brees threw for 446 passing yards and three touchdowns, Rodgers was the more efficient quarterback.
Rodgers and Green Bay’s offense converted an impressive 30 first downs, which was the most by a Packers team since November 12, 1989. Rodgers was also 4-for-8 on third down conversions and 1-for-1 on fourth down. It should also be noted the Packers ran 66 plays on offense for a season-high 421 total yards.
Rodgers connected with eight different receivers, including hitting Jordy Nelson eight times for 93 yards and the go-ahead touchdown when the Packers were trailing by six late in the fourth quarter. This is Green Bay’s 23rd victory when Rodgers has a passer rating over 115 and their eighth win when he throws at least four touchdown passes. The Packers have never lost a game in either circumstance with Rodgers under center.
This is just one more award for an outstanding football player. After looking at other offensive player performances in the NFL this past week, Rodgers is clearly the most deserving to be recognized. His numbers were outstanding but the fact he was able to keep his cool when everything seemed to be going against Green Bay is the true reason he received the mention.
Rodgers has won the Player of the Week Award six times in his career.
Michael is a MLB and NBA Featured Writer for Rant Sports, but covers topics for various teams in baseball, basketball, and football. Make sure to follow Michael on Twitter @MichaelTerrill and on Facebook.