What Ahmad Bradshaw Visiting Indianapolis Colts Could Mean to Donald Brown

David Butler II-USA TODAY Sports

It’s been confirmed that former New York Giants running back Ahmad Bradshaw is in town today visiting the Indianapolis Colts. There’s a mutual interest between both, and with many other franchises picking rookie running backs in the draft, the Colts are now the front runner to land Bradshaw.

If the Colts do indeed sign Bradshaw that means one of the current three running backs will likely be released. That odd man out would likely be Donald Brown.

The Colts certainly won’t release Vick Ballard who’s entering his second season with the team. Ballard rushed for 814 yards and three touchdowns last season as a rookie and didn’t really get playing time until the fifth game of the season. If he had played all year he would have been a 1,000+ yard rusher.

The team has said Ballard is likely going to be No. 1 on the depth chart this year.

With Bradshaw possibly coming in he would be the backup behind Ballard. He’s very good at splitting carries and very effective when in the game. He’s a very underrated pass protector out of the backfield and can also catch passes.

That leaves the final spot between Delone Carter and Donald Brown because there’s no way the Colts would keep four running backs on the active roster. That’s way too many.

My money would be on Carter staying and Brown being released. Brown has been very up and down in his time with the Colts, and it’s been rumored over the past couple of seasons that he would be gone.

Brown is a strictly run outside the tackles back and either gets big gains or none at all. He’s proven to be anything but an every down back.

Then there’s Carter who’s the opposite of everyone else. He’s a bruiser that loves to run in between the tackles and can give Colts gains in short yardage situations. That’s something the other three aren’t built to do which is why I feel Carter will be kept and Brown will be gone with a Bradshaw signing.


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