The Chicago Bears decided it was a good idea to start injured quarterback Jay Cutler against the Detroit Lions on Sunday. As many pointed out late last week, it was a decision that could certainly cost the Bears dearly.
At this point, it is unknown how big of an effect head coach Marc Trestman’s decision to allow Cutler to suit up will have on the team. However, there is no question it will affect the outcome of the season one way or another.
Trestman himself admitted on Monday that he never should allowed Cutler to play as much as he did, especially since the signal caller had to deal with a strained groin muscle and a left ankle injury that he suffered in the first half.
“I went through the tape closely this morning and watched Jay’s performance, and I thought he did well into the fourth quarter,” Trestman said, according to ESPN.com. “But at the end of the day, if we had to do it all over again, maybe it would be one series before the two-minute drill [that Cutler comes out].”
The fact is Josh McCown was playing well prior to Sunday’s contest. The 11-year veteran completed 59.0 percent of his 61 pass attempts for 476 passing yards, three touchdowns, zero interceptions and a 100.2 passer rating heading into Chicago’s showdown with Detroit. He developed some chemistry with the wide receivers and running back Matt Forte, which is what the Bears should have taken into consideration.
It was obvious Cutler was a little off with his throws. No one can really blame him considering it was just three weeks ago that he suffered a groin tear.
Even though it was a huge contest against a division rival with first place in the NFC North on the line, the Bears should have stuck with McCown. He had plenty of momentum after a huge win against an Aaron Rodgers-less Green Bay Packers at Lambeau Field. He could have used that momentum to help the offense score more than three touchdowns against the Lions.
One has to wonder if the loss in Week 10 will be enough for Chicago to miss out on the playoffs completely, especially if Cutler is unable to remain healthy.